Monday, September 5, 2011

8/30 Fluid Statics

Introduction:

   The purpose of this experiment is measure the buoyant force with three different methods. At the end, we compared the three results.

 Experiment

PartA:

B = W-T

B= 0.54N-0.35N=0.19N

Part B:
In part B, we used a different method which is fill the beaker with water and measure the mass (beaker+water). Later, we put the mass into the water then measure the mass of beaker again



Mass of beaker + water before : 236.3g
Mass of beaker + water after: 226.1g
Thus, mass of water = 0.102kg
W of water = 0.10N

Part C:
V: pi*r^2*h
h: 5.1cm
D;1.6cm
V=1.025*10^-5 m^3

W= density*volume*g

W=0.101N

Conclusion:

Even though the three results are not quiet the same, all three results are in the same order of magnitude. In the first experiment, we used a force measured device the weight the mass before submerged into water and after. The different of the forces should be the buoyant force provided by the water. In this experiment, we did not include the mass of the string. Also, we are not sure if the device is as accurate as possible. In the second experiment, we put the mass into the water and measured the different between the change in water to determine the buoyant force due to the water. In this experiment, there are many places that can caused errors occurred such  as the surface tension of the water, shape of the beaker, and the water drop that stayed around the beaker. In the last experiment, we measured the volume of the mass and times it with the density of the water and gravity inorder to figure the buoyant force. Again, we did not consider the shape of the object is uniform nor the dimension of the shape is actually a cylinder.

With all the possible errors occurred in each of the experiment, we can conclude that  the results math each others. Overall, the last experiment  should be the most accurate one because it has the least amount of possible error.

In the first part of the experiment, if we let the mass touching the bottom of the beaker, the reading of the device will be reaching zero due to the normal force that produced by the beaker. Thus, the value of the buoyant force will be very large instead.

No comments:

Post a Comment